Solve the quadratic by factoring. 5x^(2)-15 x+7=6x+3 Answer: x=

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Solve the quadratic by factoring.  5x^(2)-15 x+7=6x+3 Answer:  x=

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Write Standard Form: Write the quadratic equation in standard form by moving all terms to one side. Subtract 6x and 3 from both sides of the equation. 5x^2 - 15x + 7 = 6x + 3 becomes 5x^2 - 15x - 6x + 7 - 3 = 0. Combine like terms. 5x^2 - 21x + 4 = 0.Subtract Terms: Factor the quadratic equation. We need to find two numbers that multiply to 5 * 4 = 20 and add up to -21. The numbers that satisfy these conditions are -20 and -1. Rewrite the middle term using these two numbers. 5x^2 - 20x - x + 4 = 0.Factor Quadratic Equation: Factor by grouping. Group the terms to factor by common factors. (5x^2 - 20x) - (x - 4) = 0. Factor out the common factors from each group. 5x(x - 4) - 1(x - 4) = 0.Factor by Grouping: Factor out the common binomial factor. Since both terms contain (x - 4), factor it out. (5x - 1)(x - 4) = 0.Factor Common Binomial: Solve the factored equation for x. Set each factor equal to zero and solve for x. 5x - 1 = 0 and x - 4 = 0. Solve the first equation: 5x = 1 so x = 1/5. Solve the second equation: x = 4.

Solve the quadratic by factoring. $\newline$ $5 x^{2}-15 x+7=6 x+3$ $\newline$ Answer: $x=$

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Solve the quadratic by factoring.\newline5x2−15x+7=6x+3 5 x^{2}-15 x+7=6 x+3 5x2−15x+7=6x+3\newlineAnswer: x= x= x=

Solve the quadratic by factoring. $\newline$ $5 x^{2}-15 x+7=6 x+3$ $\newline$ Answer: $x=$