Solve the quadratic by factoring. 5x^(2)+1=36 x-6 Answer: x=

Write Standard Form: Write the quadratic equation in standard form. To solve the quadratic by factoring, we need to have it in the form ax^2 + bx + c = 0. So we will move all terms to one side of the equation. 5x^2 + 1 = 36x - 6 Subtract 36x and add 6 to both sides to get: 5x^2 - 36x + 7 = 0Move Terms: Factor the quadratic equation. We need to find two numbers that multiply to (5)(7) = 35 and add up to -36. However, there are no two integers that satisfy these conditions. Therefore, this quadratic equation cannot be factored using integers. We may need to use the quadratic formula to find the solutions.

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Solve the quadratic by factoring.

5x^(2)+1=36 x-6
Answer:
x=

Solve the quadratic by factoring. $\newline$ $5 x^{2}+1=36 x-6$ $\newline$ Answer: $x=$

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Algebra 1

Factor quadratics with other leading coefficients

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Q. Solve the quadratic by factoring.

\newline

5 x^{2}+1=36 x-6

\newline

Answer:

x=

Write Standard Form: Write the quadratic equation in standard form. $\newline$ To solve the quadratic by factoring, we need to have it in the form $ax^2 + bx + c = 0$ . So we will move all terms to one side of the equation. $\newline$ $5x^2 + 1 = 36x - 6$ $\newline$ Subtract $36x$ and add $6$ to both sides to get: $\newline$ $5x^2 - 36x + 7 = 0$
Move Terms: Factor the quadratic equation. $\newline$ We need to find two numbers that multiply to $(5)(7) = 35$ and add up to $-36$ . However, there are no two integers that satisfy these conditions. Therefore, this quadratic equation cannot be factored using integers. We may need to use the quadratic formula to find the solutions.