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Solve the quadratic by factoring.

4x^(2)-9x+5=3
Answer: 
x=

Solve the quadratic by factoring.\newline4x29x+5=3 4 x^{2}-9 x+5=3 \newlineAnswer: x= x=

Full solution

Q. Solve the quadratic by factoring.\newline4x29x+5=3 4 x^{2}-9 x+5=3 \newlineAnswer: x= x=
  1. Set Quadratic Equation to Zero: First, we need to set the quadratic equation to zero by subtracting 33 from both sides of the equation.\newline4x29x+53=04x^2 - 9x + 5 - 3 = 0\newlineSimplify the equation:\newline4x29x+2=04x^2 - 9x + 2 = 0
  2. Identify Coefficients: Identify the coefficients aa, bb, and cc in the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0.\newlineIn the equation 4x29x+2=04x^2 - 9x + 2 = 0, we have:\newlinea=4a = 4\newlineb=9b = -9\newlinec=2c = 2
  3. Find Two Numbers: Find two numbers that multiply to aca*c (which is 42=84*2 = 8) and add up to bb (which is 9-9).\newlineThe two numbers that satisfy these conditions are 8-8 and 1-1 because:\newline8×1=8-8 \times -1 = 8\newline8+1=9-8 + -1 = -9
  4. Rewrite Middle Term: Rewrite the middle term, 9x-9x, using the two numbers found in the previous step.\newline4x29x+2=4x28xx+24x^2 - 9x + 2 = 4x^2 - 8x - x + 2
  5. Factor by Grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(4x28x)+(x+2)(4x^2 - 8x) + (-x + 2)\newlineFactor out the common factors from each group.\newline4x(x2)1(x2)4x(x - 2) - 1(x - 2)
  6. Factor Out Common Factors: Since both groups contain the common factor (x2)(x - 2), factor it out.(4x1)(x2)=0(4x - 1)(x - 2) = 0
  7. Set Factors Equal to Zero: Set each factor equal to zero and solve for xx.4x1=04x - 1 = 0 or x2=0x - 2 = 0For the first equation, add 11 to both sides:4x=14x = 1Divide by 44:x=14x = \frac{1}{4}For the second equation, add 22 to both sides:x=2x = 2