Q. Solve the quadratic by factoring.4x2−9x+5=3Answer: x=
Set Quadratic Equation to Zero: First, we need to set the quadratic equation to zero by subtracting 3 from both sides of the equation.4x2−9x+5−3=0Simplify the equation:4x2−9x+2=0
Identify Coefficients: Identify the coefficients a, b, and c in the quadratic equation ax2+bx+c=0.In the equation 4x2−9x+2=0, we have:a=4b=−9c=2
Find Two Numbers: Find two numbers that multiply to a∗c (which is 4∗2=8) and add up to b (which is −9).The two numbers that satisfy these conditions are −8 and −1 because:−8×−1=8−8+−1=−9
Rewrite Middle Term: Rewrite the middle term, −9x, using the two numbers found in the previous step.4x2−9x+2=4x2−8x−x+2
Factor by Grouping: Factor by grouping. Group the first two terms together and the last two terms together.(4x2−8x)+(−x+2)Factor out the common factors from each group.4x(x−2)−1(x−2)
Factor Out Common Factors: Since both groups contain the common factor (x−2), factor it out.(4x−1)(x−2)=0
Set Factors Equal to Zero: Set each factor equal to zero and solve for x.4x−1=0 or x−2=0For the first equation, add 1 to both sides:4x=1Divide by 4:x=41For the second equation, add 2 to both sides:x=2
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