Solve the quadratic by factoring. 4x^(2)-3x+12=5x+9 Answer: x=

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Solve the quadratic by factoring.  4x^(2)-3x+12=5x+9 Answer:  x=

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Move to Standard Form: Write the equation in standard form by moving all terms to one side of the equation. Subtract 5x and 9 from both sides of the equation 4x^2 - 3x + 12 = 5x + 9. 4x^2 - 3x + 12 - 5x - 9 = 0 Combine like terms. 4x^2 - 8x + 3 = 0Identify Coefficients: Identify a, b, and c in the standard form of the quadratic equation ax^2 + bx + c = 0. From 4x^2 - 8x + 3 = 0, we have: a = 4 b = -8 c = 3Find Multiplying Numbers: Find two numbers that multiply to a*c (4*3=12) and add up to b (-8). We need to find two numbers that multiply to 12 and add up to -8. However, there are no two such integers that satisfy both conditions. This means the quadratic cannot be factored using integers.Conclusion: Since the quadratic cannot be factored using integers, we can conclude that the quadratic equation does not have a solution that can be expressed as a factoring of integers. We may need to use other methods such as completing the square or the quadratic formula to find the solutions.

Solve the quadratic by factoring. $\newline$ $4 x^{2}-3 x+12=5 x+9$ $\newline$ Answer: $x=$

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Solve the quadratic by factoring.\newline4x2−3x+12=5x+9 4 x^{2}-3 x+12=5 x+9 4x2−3x+12=5x+9\newlineAnswer: x= x= x=

Solve the quadratic by factoring. $\newline$ $4 x^{2}-3 x+12=5 x+9$ $\newline$ Answer: $x=$