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Solve the quadratic by factoring.

3x^(2)+5x-9=-7
Answer: 
x=

Solve the quadratic by factoring.\newline3x2+5x9=7 3 x^{2}+5 x-9=-7 \newlineAnswer: x= x=

Full solution

Q. Solve the quadratic by factoring.\newline3x2+5x9=7 3 x^{2}+5 x-9=-7 \newlineAnswer: x= x=
  1. Move and Combine Terms: First, we need to move all terms to one side of the equation to set it equal to zero.\newline3x2+5x9+7=03x^2 + 5x - 9 + 7 = 0\newlineNow, combine like terms.\newline3x2+5x2=03x^2 + 5x - 2 = 0
  2. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0.\newlineFor the equation 3x2+5x2=03x^2 + 5x - 2 = 0, we have:\newlinea=3a = 3\newlineb=5b = 5\newlinebb00
  3. Find Multiplying Numbers: Find two numbers that multiply to aca*c (which is 3(2)=63*(-2) = -6) and add up to bb (which is 55).\newlineThe numbers that satisfy these conditions are 66 and 1-1 because:\newline6(1)=66 * (-1) = -6 (product is aca*c)\newline6+(1)=56 + (-1) = 5 (sum is bb)
  4. Rewrite Middle Term: Rewrite the middle term 5x5x using the two numbers found in the previous step. 3x2+6xx2=03x^2 + 6x - x - 2 = 0 Now we have four terms and can proceed with factoring by grouping.
  5. Factor by Grouping: Group the terms to factor by grouping.\newline(3x2+6x)(x+2)=0(3x^2 + 6x) - (x + 2) = 0\newlineFactor out the common factors from each group.\newline3x(x+2)1(x+2)=03x(x + 2) - 1(x + 2) = 0
  6. Factor Out Common Factor: Now that we have a common factor of (x+2)(x + 2), factor it out.(3x1)(x+2)=0(3x - 1)(x + 2) = 0
  7. Set Factors Equal: Set each factor equal to zero and solve for xx.\newlineFirst factor: 3x1=03x - 1 = 0\newlineAdd 11 to both sides: 3x=13x = 1\newlineDivide by 33: x=13x = \frac{1}{3}
  8. Solve for x: Now solve for x using the second factor.\newlineSecond factor: x+2=0x + 2 = 0\newlineSubtract 22 from both sides: x=2x = -2