Q. Solve the quadratic by factoring.3x2+15=19x+9Answer: x=
Write Standard Form: Write the quadratic equation in standard form.We need to bring all terms to one side of the equation to have it in the form ax2+bx+c=0.3x2+15=19x+9Subtract 19x and 9 from both sides to get:3x2−19x+15−9=03x2−19x+6=0
Identify a, b, c: Identify a, b, and c in the standard form of the quadratic equation.From 3x2−19x+6=0, we can see that:a=3b=−19c=6
Find Multiplying Numbers: Find two numbers that multiply to a∗c (3∗6=18) and add up to b (−19).We need to find two numbers that multiply to 18 and add up to −19. These numbers are −3 and −16 because:−3∗−16=18−3+−16=−19
Rewrite Using Numbers: Rewrite the quadratic equation using the numbers found in Step 3 to split the middle term.We can split the middle term −19x into −3x−16x:3x2−3x−16x+6=0
Factor by Grouping: Factor by grouping.Group the first two terms and the last two terms:(3x2−3x)−(16x−16)=0Factor out the greatest common factor from each group:3x(x−1)−2(8x−3)=0
Factor Common Binomial: Factor out the common binomial factor.We need to rewrite the expression so that we have a common factor to factor out. However, we see that there is no common binomial factor between 3x(x−1) and 2(8x−3). This indicates that there is a mistake in the previous steps.
More problems from Factor quadratics with other leading coefficients