Q. Solve the equation given below and find the value of x and yx+y=3x−y=1
Given Equations: Given the system of equations:1. x+y=32. x−y=1We will solve this system using the method of elimination.
Addition to Eliminate y: Add the two equations together to eliminate y:(x+y)+(x−y)=3+12x=4Now, divide both sides by 2 to solve for x:x=24x=2
Solving for x: Substitute the value of x back into one of the original equations to solve for y. We'll use the first equation:x+y=32+y=3Now, subtract 2 from both sides to solve for y:y=3−2y=1
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