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Solve the equation for all values of 
x.

|x+1|+7=2x
Answer: 
x=

Solve the equation for all values of x x .\newlinex+1+7=2x |x+1|+7=2 x \newlineAnswer: x= x=

Full solution

Q. Solve the equation for all values of x x .\newlinex+1+7=2x |x+1|+7=2 x \newlineAnswer: x= x=
  1. Introduction: We have the equation x+1+7=2x|x+1| + 7 = 2x. To solve for xx, we need to consider two cases because the absolute value function yields two possible scenarios: one where the expression inside the absolute value is non-negative (x+10x+1 \geq 0) and one where it is negative (x+1 < 0).
  2. Case 11: Non-negative xx: First, let's consider the case where x+1x+1 is non-negative, which means x+10x+1 \geq 0 or x1x \geq -1. In this case, the absolute value function does not change the sign of the expression inside it.\newlineSo, we have x+1+7=2xx+1 + 7 = 2x.\newlineNow, let's solve for xx.\newlinex+1+7=2xx + 1 + 7 = 2x\newlinex+8=2xx + 8 = 2x\newlineSubtract xx from both sides:\newline8=x8 = x
  3. Case 22: Negative xx: Now, let's consider the case where x+1x+1 is negative, which means x+1 < 0 or x < -1. In this case, the absolute value function will change the sign of the expression inside it.\newlineSo, we have (x+1)+7=2x- (x+1) + 7 = 2x.\newlineNow, let's solve for xx.\newline(x+1)+7=2x- (x + 1) + 7 = 2x\newlinex1+7=2x- x - 1 + 7 = 2x\newline6x=2x6 - x = 2x\newlineAdd xx to both sides:\newlinex+1x+100\newlineDivide both sides by x+1x+111:\newlinex+1x+122
  4. Solutions Analysis: We have found two potential solutions, x=8x = 8 and x=2x = 2. However, we must check these solutions against the original conditions we set for each case. For x=8x = 8, the condition was x1x \geq -1, which is true. For x=2x = 2, the condition was x < -1, which is not true. Therefore, x=2x = 2 is not a valid solution to the original equation.
  5. Valid Solution: The only solution that satisfies the original equation and the conditions we set is x=8x = 8.

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