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Solve the equation for all values of 
x.

|3x-4|=x
Answer: 
x=

Solve the equation for all values of x x .\newline3x4=x |3 x-4|=x \newlineAnswer: x= x=

Full solution

Q. Solve the equation for all values of x x .\newline3x4=x |3 x-4|=x \newlineAnswer: x= x=
  1. Absolute Value Equation: We have the equation 3x4=x|3x - 4| = x. To solve this, we need to consider two cases because the absolute value function outputs the distance from zero, which can be either positive or negative.\newlineCase 11: When the expression inside the absolute value is non-negative, we can remove the absolute value bars without changing the sign.\newlineCase 22: When the expression inside the absolute value is negative, we remove the absolute value bars and change the sign of the expression inside.
  2. Case 11 Solution: Solve for Case 11 where the expression inside the absolute value is non-negative.\newline3x4=x3x - 4 = x\newlineSubtract xx from both sides to get the xx terms on one side.\newline3xx4=xx3x - x - 4 = x - x\newline2x4=02x - 4 = 0\newlineAdd 44 to both sides to isolate the term with xx.\newline2x4+4=0+42x - 4 + 4 = 0 + 4\newline2x=42x = 4\newlineDivide both sides by 22 to solve for xx.\newlinexx11\newlinexx22
  3. Case 22 Solution: Solve for Case 22 where the expression inside the absolute value is negative.\newline3x4=x-3x - 4 = x\newlineDistribute the negative sign inside the parentheses.\newline3x+4=x-3x + 4 = x\newlineAdd 3x3x to both sides to get the xx terms on one side.\newline3x+3x+4=x+3x-3x + 3x + 4 = x + 3x\newline4=4x4 = 4x\newlineDivide both sides by 44 to solve for xx.\newline44=4x4\frac{4}{4} = \frac{4x}{4}\newline1=x1 = x
  4. Check Solutions: Check the solutions in the original equation to ensure they do not result in a negative inside the absolute value when it should be positive or vice versa.\newlineFor x=2x = 2:\newline3(2)4=2|3(2) - 4| = 2\newline64=2|6 - 4| = 2\newline2=2|2| = 2\newline2=22 = 2 which is true.\newlineFor x=1x = 1:\newline3(1)4=1|3(1) - 4| = 1\newline34=1|3 - 4| = 1\newline1=1|-1| = 1\newline1=11 = 1 which is true.\newlineBoth solutions satisfy the original equation.

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