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Solve the equation for all values of 
x.

|2x+1|-8=x
Answer: 
x=

Solve the equation for all values of x x .\newline2x+18=x |2 x+1|-8=x \newlineAnswer: x= x=

Full solution

Q. Solve the equation for all values of x x .\newline2x+18=x |2 x+1|-8=x \newlineAnswer: x= x=
  1. Consider Non-Negative Case: We have the equation 2x+18=x|2x+1|-8=x. To solve for xx, we need to consider two cases because of the absolute value: one where 2x+12x+1 is non-negative and one where 2x+12x+1 is negative.
  2. Simplify Non-Negative Case: First, let's consider the case where 2x+12x+1 is non-negative. In this case, the absolute value expression 2x+1|2x+1| is just 2x+12x+1. So the equation becomes:\newline2x+18=x2x+1-8=x
  3. Isolate Variable (Non-Negative): Simplify the equation by subtracting 11 and adding 88 to both sides:\newline2x+18=x2x+1-8=x\newline2x7=x2x-7=x
  4. Add 77 (Non-Negative): Now, subtract xx from both sides to isolate the variable:\newline2x7x=xx2x-7-x=x-x\newlinex7=0x-7=0
  5. Consider Negative Case: Add 77 to both sides to solve for xx: \newlinex7+7=0+7x-7+7=0+7\newlinex=7x=7\newlineThis is the solution for the case where 2x+12x+1 is non-negative.
  6. Distribute Negative Sign: Now, let's consider the case where 2x+12x+1 is negative. In this case, the absolute value expression 2x+1|2x+1| is (2x+1)-(2x+1). So the equation becomes:\newline(2x+1)8=x-(2x+1)-8=x
  7. Combine Like Terms: Distribute the negative sign inside the parentheses: 2x18=x-2x-1-8=x
  8. Isolate Variable (Negative): Combine like terms by adding 11 and 88 to both sides:\newline2x18+1+8=x+1+8-2x-1-8+1+8=x+1+8\newline2x=x+9-2x=x+9
  9. Subtract 99: Add 2x2x to both sides to isolate the variable:\newline2x+2x=x+9+2x-2x+2x=x+9+2x\newline0=3x+90=3x+9
  10. Divide by 33: Subtract 99 from both sides to solve for xx: \newline09=3x+990-9=3x+9-9\newline9=3x-9=3x
  11. Divide by 33: Subtract 99 from both sides to solve for xx: \newline09=3x+990-9=3x+9-9\newline9=3x-9=3xDivide both sides by 33 to find the value of xx: \newline93=3x3-\frac{9}{3}=\frac{3x}{3}\newline3=x-3=x\newlineThis is the solution for the case where 2x+12x+1 is negative.

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