Q. Solve the equation for all values of x.∣2x−1∣+5=4xAnswer: x=
Consider Non-Negative Case: We have the equation ∣2x−1∣+5=4x. To solve for x, we need to consider two cases because of the absolute value: one where 2x−1 is non-negative, and one where 2x−1 is negative.
Simplify Equation: First, let's consider the case where 2x−1 is non-negative, which means 2x−1≥0. In this case, the absolute value expression ∣2x−1∣ is just 2x−1. So the equation becomes:2x−1+5=4x
Isolate x: Simplify the equation by combining like terms: 2x+4=4x
Check Validity for x=2: To isolate x, we subtract 2x from both sides of the equation:4=2x
Consider Negative Case: Divide both sides by 2 to solve for x: x=2
Distribute Negative Sign: Now, let's consider the second case where 2x−1 is negative, which means 2x - 1 < 0. In this case, the absolute value expression ∣2x−1∣ is −(2x−1). So the equation becomes:−(2x−1)+5=4x
Combine Like Terms: Distribute the negative sign inside the parentheses: −2x+1+5=4x
Divide by 6: Combine like terms:6=6x
Check Validity for x=1: Divide both sides by 6 to solve for x:x=1
Check Validity for x=1: Divide both sides by 6 to solve for x:x=1We need to check if our solutions satisfy the original equation. For x=2, the original equation ∣2x−1∣+5=4x becomes ∣4−1∣+5=8, which simplifies to 3+5=8. This is true, so x=2 is a valid solution.
Check Validity for x=1: Divide both sides by 6 to solve for x:x=1We need to check if our solutions satisfy the original equation. For x=2, the original equation ∣2x−1∣+5=4x becomes ∣4−1∣+5=8, which simplifies to 3+5=8. This is true, so x=2 is a valid solution.For x=1, the original equation ∣2x−1∣+5=4x becomes 61, which simplifies to 62. This is not true, so x=1 is not a valid solution.
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