Solve the equation. Check your solution. -3p+3=12 The solution set is _____.

Isolate variable term: Isolate the variable term on one side of the equation. To do this, we subtract 3 from both sides of the equation to get -3p on one side. -3p + 3 - 3 = 12 - 3 This simplifies to: -3p = 9Solve for p: Solve for p by dividing both sides of the equation by -3. -3p / -3 = 9 / -3 This simplifies to: p = -3Check solution: Check the solution by substituting p = -3 back into the original equation. -3(-3) + 3 = 12 9 + 3 = 12 12 = 12 The left side of the equation equals the right side, which means our solution is correct.

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Solve the equation. Check your solution.
-3p+3=12
The solution set is _____.

Solve the equation. Check your solution. $\newline$ $-3 p+3=12$ $\newline$ The solution set is $\_\_\_\_\_$ .

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Math Problems

Grade 8

Checkpoint: Rational and irrational numbers

Full solution

Q. Solve the equation. Check your solution.

\newline

-3 p+3=12

\newline

The solution set is

\_\_\_\_\_

Isolate variable term: Isolate the variable term on one side of the equation. $\newline$ To do this, we subtract $3$ from both sides of the equation to get $-3p$ on one side. $\newline$ $-3p + 3 - 3 = 12 - 3$ $\newline$ This simplifies to: $\newline$ $-3p = 9$
Solve for p: Solve for p by dividing both sides of the equation by -3＂).$\newline\$-3p / -3 = 9 / -3$$\newline$This simplifies to:$\newline$$p = -3$
Check solution: Check the solution by substituting $p = -3$ back into the original equation.$\newline$$-3(-3) + 3 = 12$$\newline$$9 + 3 = 12$$\newline$$12 = 12$$\newline$The left side of the equation equals the right side, which means our solution is correct.