Solve the equation. Check your solution. 18=6-(z+8)

Isolate variable term: Isolate the variable term on one side of the equation. We start by adding (z+8) to both sides of the equation to isolate the variable term on one side. 18 = 6 - (z + 8) 18 + (z + 8) = 6 - (z + 8) + (z + 8) 18 + z + 8 = 6Combine like terms: Combine like terms. Now we combine the constants on the left side of the equation. 18 + 8 = 26 So, we have: 26 + z = 6Isolate variable z: Isolate the variable z. To isolate z, we subtract 26 from both sides of the equation. 26 + z - 26 = 6 - 26 z = -20Check solution: Check the solution. We substitute z = -20 back into the original equation to check if it is correct. 18 = 6 - ((-20) + 8) 18 = 6 - (-12) 18 = 6 + 12 18 = 18 The solution checks out.

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Solve the equation. Check your solution. $\newline$ $18=6-(z+8)$ $\newline$

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Algebra 2

Sin, cos, and tan of special angles

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Q. Solve the equation. Check your solution.

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18=6-(z+8)

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Isolate variable term: Isolate the variable term on one side of the equation. $\newline$ We start by adding $z+8$ to both sides of the equation to isolate the variable term on one side. $\newline$ $18 = 6 - (z + 8)$ $\newline$ $18 + (z + 8) = 6 - (z + 8) + (z + 8)$ $\newline$ $18 + z + 8 = 6$
Combine like terms: Combine like terms. $\newline$ Now we combine the constants on the left side of the equation. $\newline$ $18 + 8 = 26$ $\newline$ So, we have: $\newline$ $26 + z = 6$
Isolate variable z: Isolate the variable z. $\newline$ To isolate z, we subtract $26$ from both sides of the equation. $\newline$ $26 + z - 26 = 6 - 26$ $\newline$ $z = -20$
Check solution: Check the solution. $\newline$ We substitute $z = -20$ back into the original equation to check if it is correct. $\newline$ $18 = 6 - ((-20) + 8)$ $\newline$ $18 = 6 - (-12)$ $\newline$ $18 = 6 + 12$ $\newline$ $18 = 18$ $\newline$ The solution checks out.