Solve the equation by factoring: 168 x+3x^(2)-3x^(3)=0 Answer: x=

Factor GCF: Factor out the greatest common factor (GCF) Identify the GCF of the terms in the equation. The GCF of 168x, 3x^2, and -3x^3 is 3x. Factor out 3x from each term. 3x(56 + x - x^2) = 0Rewrite Quadratic: Rewrite the quadratic in standard form The quadratic part of the factored expression is currently in the form -x^2 + x + 56. We need to rewrite it in standard form, which is ax^2 + bx + c. So, we have 3x(-x^2 + x + 56) = 0. Rewrite it as 3x(-(x^2 - x - 56)) = 0.Factor Expression: Factor the quadratic expression Now we need to factor the quadratic expression -x^2 + x + 56. We are looking for two numbers that multiply to -56 and add up to 1. The numbers are 8 and -7. So, the factored form is 3x(-(x - 8)(x + 7)) = 0.Set Equal: Set each factor equal to zero Now we have the factored form of the equation: 3x(x - 8)(x + 7) = 0. Set each factor equal to zero to find the solutions for x. 3x = 0, x - 8 = 0, and x + 7 = 0.Solve for x: Solve for x Solve each equation for x. For 3x = 0, x = 0. For x - 8 = 0, x = 8. For x + 7 = 0, x = -7.

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Solve the equation by factoring:

168 x+3x^(2)-3x^(3)=0
Answer:
x=

Solve the equation by factoring: $\newline$ $168 x+3 x^{2}-3 x^{3}=0$ $\newline$ Answer: $x=$

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Math Problems

Algebra 2

Sum of finite series not start from 1

Full solution

Q. Solve the equation by factoring:

\newline

168 x+3 x^{2}-3 x^{3}=0

\newline

Answer:

x=

Factor GCF: Factor out the greatest common factor (GCF) $\newline$ Identify the GCF of the terms in the equation. $\newline$ The GCF of $168x$ , $3x^2$ , and $-3x^3$ is $3x$ . $\newline$ Factor out $3x$ from each term. $\newline$ $3x(56 + x - x^2) = 0$
Rewrite Quadratic: Rewrite the quadratic in standard form $\newline$ The quadratic part of the factored expression is currently in the form $-x^2 + x + 56$ . We need to rewrite it in standard form, which is $ax^2 + bx + c$ . $\newline$ So, we have $3x(-x^2 + x + 56) = 0$ . $\newline$ Rewrite it as $3x(-(x^2 - x - 56)) = 0$ .
Factor Expression: Factor the quadratic expression $\newline$ Now we need to factor the quadratic expression -x^2 + x + 56＂).$\newlineWe are looking for two numbers that multiply to \$-56$ and add up to $1$.$\newline$The numbers are $8$ and $-7$.$\newline$So, the factored form is $3x(-(x - 8)(x + 7)) = 0$.
Set Equal: Set each factor equal to zero$\newline$Now we have the factored form of the equation: $3x(x - 8)(x + 7) = 0$.$\newline$Set each factor equal to zero to find the solutions for $x$.$\newline$$3x = 0$, $x - 8 = 0$, and $x + 7 = 0$.
Solve for x: Solve for x$\newline$Solve each equation for x.$\newline$For $3x = 0$, $x = 0$.$\newline$For $x - 8 = 0$, $x = 8$.$\newline$For $x + 7 = 0$, $x = -7$.