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Solve the equation below for xx in terms of aa.\newline4(ax+3)3ax=25+3a4(a x + 3) - 3 a x = 25 + 3 a

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Q. Solve the equation below for xx in terms of aa.\newline4(ax+3)3ax=25+3a4(a x + 3) - 3 a x = 25 + 3 a
  1. Expand Equation: Expand the left side of the equation.\newline4(ax+3)3ax=4ax+123ax4(ax+3)-3ax = 4ax + 12 - 3ax
  2. Combine Like Terms: Combine like terms on the left side.\newline4ax+123ax=(4ax3ax)+12=ax+124ax + 12 - 3ax = (4ax - 3ax) + 12 = ax + 12
  3. Rewrite Equation: Rewrite the equation with the combined terms. ax+12=25+3aax + 12 = 25 + 3a
  4. Subtract 3a3a: Subtract 3a3a from both sides to isolate terms with xx on one side.\newlineax+123a=25+3a3aax + 12 - 3a = 25 + 3a - 3a
  5. Simplify Equation: Simplify both sides of the equation. ax+123a=25ax + 12 - 3a = 25
  6. Subtract 1212: Subtract 1212 from both sides to solve for axax.\newlineax=2512+3aax = 25 - 12 + 3a
  7. Combine Constants: Combine the constants on the right side. ax=13+3aax = 13 + 3a
  8. Isolate xx: Isolate xx by dividing both sides by aa.x=13+3aax = \frac{13 + 3a}{a}

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