Solve the equation 5x^(2)-18 x+5=-6x to the nearest tenth. Answer: x=

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Solve the equation  5x^(2)-18 x+5=-6x to the nearest tenth. Answer:  x=

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Move terms to one side: First, we need to move all terms to one side of the equation to set the equation to zero. We do this by adding 6x to both sides of the equation. 5x^2 - 18x + 5 + 6x = 0 5x^2 - 12x + 5 = 0Solve quadratic equation: Next, we need to solve the quadratic equation. We can either factor the quadratic, complete the square, or use the quadratic formula. The quadratic formula is $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $, where a, b, and c are the coefficients from the quadratic equation ax^2 + bx + c = 0. In our case, a = 5, b = -12, and c = 5.Plug values into formula: Now we will plug the values of a, b, and c into the quadratic formula to find the values of x. x = $\frac{-(-12) \pm \sqrt{(-12)^2 - 4(5)(5)}}{2(5)}$ x = $\frac{12 \pm \sqrt{144 - 100}}{10}$ x = $\frac{12 \pm \sqrt{44}}{10}$Simplify and divide: We simplify under the square root and then divide by 10. x = $\frac{12 \pm \sqrt{44}}{10}$ x = $\frac{12 \pm 2\sqrt{11}}{10}$ x = $\frac{6 \pm \sqrt{11}}{5}$Calculate decimal values: Now we calculate the approximate decimal values for the two solutions. x ≈ $\frac{6 + \sqrt{11}}{5}$ and x ≈ $\frac{6 - \sqrt{11}}{5}$ x ≈ $\frac{6 + 3.317}{5}$ and x ≈ $\frac{6 - 3.317}{5}$ x ≈ $\frac{9.317}{5}$ and x ≈ $\frac{2.683}{5}$ x ≈ 1.8634 and x ≈ 0.5366Round to nearest tenth: Finally, we round each solution to the nearest tenth. x ≈ 1.9 and x ≈ 0.5

Solve the equation $5 x^{2}-18 x+5=-6 x$ to the nearest tenth. $\newline$ Answer: $x=$

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Solve the equation 5x2−18x+5=−6x 5 x^{2}-18 x+5=-6 x 5x2−18x+5=−6x to the nearest tenth.\newlineAnswer: x= x= x=

Solve the equation $5 x^{2}-18 x+5=-6 x$ to the nearest tenth. $\newline$ Answer: $x=$