Solve for z. sqrt z = sqrt ( –2 + 3z) z = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(z))^2 = (sqrt(–2 + 3z))^2 z = –2 + 3zRearrange equation: Rearrange the equation to isolate z on one side. z - 3z = –2 -2z = –2Divide by -2: Divide both sides by -2 to solve for z. z = –2 / -2 z = 1

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Solve for $z$ . $\newline$ $\sqrt{z} = \sqrt{(-2 + 3z)}$ $\newline$ $z =$ _____

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Precalculus

Solve radical equations

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Q. Solve for

z

\newline

\sqrt{z} = \sqrt{(-2 + 3z)}

\newline

z =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{z})^2 = (\sqrt{-2 + 3z})^2$ $\newline$ $z = -2 + 3z$
Rearrange equation: Rearrange the equation to isolate $z$ on one side. $\newline$ $z - 3z = -2$ $\newline$ $-2z = -2$
Divide by $-2$ : Divide both sides by $-2$ to solve for $z$ . $z = \frac{-2}{-2}$ $z = 1$