Solve for z. sqrt –2z = sqrt ( –z + 5) z = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–2z))^2 = (sqrt(–z + 5))^2 –2z = –z + 5Add z terms: Add z to both sides to get all the z terms on one side. –2z + z = –z + z + 5 –z = 5Multiply by -1: Multiply both sides by -1 to solve for z. –1 * (–z) = –1 * 5 z = –5

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Solve for $z$ . $\newline$ $\sqrt{\,-2z} = \sqrt{\,-z + 5}$ $\newline$ $z = \,\_\_\_\_\_$

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Q. Solve for

z

\newline

\sqrt{\,-2z} = \sqrt{\,-z + 5}

\newline

z = \,\_\_\_\_\_

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-2z})^2 = (\sqrt{-z + 5})^2$ $\newline$ $-2z = -z + 5$
Add $z$ terms: Add $z$ to both sides to get all the $z$ terms on one side. $\newline$ $–2z + z = –z + z + 5$ $\newline$ $–z = 5$
Multiply by $-1$ : Multiply both sides by $-1$ to solve for $z$ . $-1 \times (\text{-}z) = -1 \times 5$ $z = \text{-}5$