Solve for z : {:[14=z-(-12)],[z=]:}

Write Equation Simplify: Write down the first equation from the system. The first equation is 14 = z - (-12). We need to simplify the right side of the equation by removing the parentheses.Solve for z: Simplify the right side of the equation. Since subtracting a negative is the same as adding a positive, we have z - (-12) = z + 12. Now the equation is 14 = z + 12.Write Second Equation: Solve for z by isolating it on one side of the equation. To do this, we subtract 12 from both sides of the equation. 14 - 12 = z + 12 - 12 This simplifies to 2 = z.Combine Results: Write down the second equation from the system. The second equation is simply z =. This indicates that z is equal to whatever value we find from the first equation.Combine the results from both equations. Since the first equation simplifies to 2 = z and the second equation is z =, we can conclude that z = 2.

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Math Problems

Grade 6

Multiply using the distributive property

Full solution

Q. Solve for

z

\newline

\begin{array}{l} 14=z-(-12) \\ z=\square \end{array}

Write Equation Simplify: Write down the first equation from the system. $\newline$ The first equation is $14 = z - (-12)$ . $\newline$ We need to simplify the right side of the equation by removing the parentheses.
Solve for $z$ : Simplify the right side of the equation. $\newline$ Since subtracting a negative is the same as adding a positive, we have $z - (-12) = z + 12$ . $\newline$ Now the equation is $14 = z + 12$ .
Write Second Equation: Solve for $z$ by isolating it on one side of the equation. $\newline$ To do this, we subtract $12$ from both sides of the equation. $\newline$ $14 - 12 = z + 12 - 12$ $\newline$ This simplifies to $2 = z$ .
Combine Results: Write down the second equation from the system. $\newline$ The second equation is simply $z =.$ $\newline$ This indicates that $z$ is equal to whatever value we find from the first equation.
Combine Results: Write down the second equation from the system. $\newline$ The second equation is simply $z =$ . $\newline$ This indicates that $z$ is equal to whatever value we find from the first equation.Combine the results from both equations. $\newline$ Since the first equation simplifies to $2 = z$ and the second equation is $z =$ , we can conclude that $z = 2$ .