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Solve for yy.\newliney=4y3\sqrt{\,-y} = \sqrt{\,-4y - 3}\newliney=_____y = \,\_\_\_\_\_

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Q. Solve for yy.\newliney=4y3\sqrt{\,-y} = \sqrt{\,-4y - 3}\newliney=_____y = \,\_\_\_\_\_
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(y)2=(4y3)2(\sqrt{-y})^2 = (\sqrt{-4y - 3})^2\newliney=4y3-y = -4y - 3
  2. Add 4y4y: Add 4y4y to both sides of the equation to start isolating yy.\newliney+4y=4y+4y3-y + 4y = -4y + 4y - 3\newline3y=33y = -3
  3. Divide by 33: Divide both sides of the equation by 33 to solve for yy.3y3=33\frac{3y}{3} = \frac{-3}{3}y=1y = -1

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