Solve for y. sqrt ( –4y + 2) = sqrt –5y y = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–4y + 2))^2 = (sqrt(–5y))^2 –4y + 2 = –5yAdd y terms: Add 5y to both sides of the equation to get all the y terms on one side. –4y + 5y + 2 = –5y + 5y y + 2 = 0Subtract to solve: Subtract 2 from both sides of the equation to solve for y. y + 2 - 2 = 0 - 2 y = -2

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Solve for $y$ . $\newline$ $\sqrt{(-4y + 2)} = \sqrt{-5y}$ $\newline$ $y =$ _____

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Q. Solve for

y

\newline

\sqrt{(-4y + 2)} = \sqrt{-5y}

\newline

y =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-4y + 2})^2 = (\sqrt{-5y})^2$ $\newline$ $-4y + 2 = -5y$
Add $y$ terms: Add $5y$ to both sides of the equation to get all the $y$ terms on one side. $\newline$ $–4y + 5y + 2 = –5y + 5y$ $\newline$ $y + 2 = 0$
Subtract to solve: Subtract $2$ from both sides of the equation to solve for $y$ . $\newline$ $y + 2 - 2 = 0 - 2$ $\newline$ $y = -2$