Solve for y. sqrt ( –1 + 2y) = sqrt y y = _____

Square Both Sides: sqrt(–1 + 2y) = sqrt(y) Square both sides of the equation to eliminate the square roots. (sqrt(–1 + 2y))^2 = (sqrt(y))^2 –1 + 2y = yIsolate Variable: We found –1 + 2y = y Isolate the variable on one side of the equation to solve for y. Subtract y from both sides. –1 + 2y - y = y - y –1 + y = 0Isolate y: We found –1 + y = 0 Isolate y by adding 1 to both sides of the equation. –1 + y + 1 = 0 + 1 y = 1

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Solve for $y$ . $\newline$ $\sqrt{\,-1 + 2y} = \sqrt{y}$ $\newline$ $y = \,\_\_\_\_\_$

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Q. Solve for

y

\newline

\sqrt{\,-1 + 2y} = \sqrt{y}

\newline

y = \,\_\_\_\_\_

Square Both Sides: $\sqrt{-1 + 2y} = \sqrt{y}$ $\newline$ Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-1 + 2y})^2 = (\sqrt{y})^2$ $\newline$ $-1 + 2y = y$
Isolate Variable: We found $-1 + 2y = y$
Isolate the variable on one side of the equation to solve for $y$ .
Subtract $y$ from both sides.
$-1 + 2y - y = y - y$
$-1 + y = 0$
Isolate y: We found $-1 + y = 0$ $\newline$ Isolate y by adding $1$ to both sides of the equation. $\newline$ $-1 + y + 1 = 0 + 1$ $\newline$ y = $1$