Solve for x. sqrt ( –9 + 5x) = sqrt 2x x = _____

Square Both Sides: Square both sides of the equation to eliminate the square roots. (sqrt(–9 + 5x))^2 = (sqrt(2x))^2 –9 + 5x = 2xMove Terms with x: Move all terms containing x to one side of the equation. 5x - 2x = 9 3x = 9Divide by 3: Divide both sides of the equation by 3 to solve for x. 3x / 3 = 9 / 3 x = 3Check Solution: Check the solution by substituting x back into the original equation to ensure both sides are equal. sqrt(–9 + 5(3)) = sqrt(2(3)) sqrt(–9 + 15) = sqrt(6) sqrt(6) = sqrt(6)

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Solve for $x$ . $\newline$ $\sqrt{(-9 + 5x)} = \sqrt{2x}$ $\newline$ $x =$ _____

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Q. Solve for

x

\newline

\sqrt{(-9 + 5x)} = \sqrt{2x}

\newline

x =

_____

Square Both Sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-9 + 5x})^2 = (\sqrt{2x})^2$ $\newline$ $-9 + 5x = 2x$
Move Terms with x: Move all terms containing x to one side of the equation. $\newline$ $5x - 2x = 9$ $\newline$ $3x = 9$
Divide by $3$ : Divide both sides of the equation by $3$ to solve for $x$ . $\frac{3x}{3} = \frac{9}{3}$ $x = 3$
Check Solution: Check the solution by substituting $x$ back into the original equation to ensure both sides are equal. $\newline$ $\sqrt{(-9 + 5(3))} = \sqrt{(2(3))}$ $\newline$ $\sqrt{(-9 + 15)} = \sqrt{(6)}$ $\newline$ $\sqrt{6} = \sqrt{6}$