Solve for x : sqrt(8x+12)-16=-10 Answer:

Add 16: Add 16 to both sides of the equation to isolate the square root on one side. sqrt(8x + 12) - 16 + 16 = -10 + 16 sqrt(8x + 12) = 6Square both sides: Square both sides of the equation to eliminate the square root. (sqrt(8x + 12))^2 = 6^2 8x + 12 = 36Subtract 12: Subtract 12 from both sides of the equation to isolate the term with the variable x. 8x + 12 - 12 = 36 - 12 8x = 24Divide by 8: Divide both sides of the equation by 8 to solve for x. 8x / 8 = 24 / 8 x = 3

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Solve for
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sqrt(8x+12)-16=-10
Answer:

Solve for $\mathrm{x}$ : $\newline$ $\sqrt{8 x+12}-16=-10$ $\newline$ Answer:

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Q. Solve for

\mathrm{x}

\newline

\sqrt{8 x+12}-16=-10

\newline

Answer:

Add $16$ : Add $16$ to both sides of the equation to isolate the square root on one side. $\newline$ $\sqrt{8x + 12} - 16 + 16 = -10 + 16$ $\newline$ $\sqrt{8x + 12} = 6$
Square both sides: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{8x + 12})^2 = 6^2$ $\newline$ $8x + 12 = 36$
Subtract $12$ : Subtract $12$ from both sides of the equation to isolate the term with the variable $x$ . $\newline$ $8x + 12 - 12 = 36 - 12$ $\newline$ $8x = 24$
Divide by $8$ : Divide both sides of the equation by $8$ to solve for x. $\newline$ $\frac{8x}{8} = \frac{24}{8}$ $\newline$ $x = 3$