Solve for x : sqrt(4x+68)-9=-1 Answer:

Add 9 to isolate square root: Add 9 to both sides of the equation to isolate the square root on one side. sqrt(4x + 68) - 9 + 9 = -1 + 9 sqrt(4x + 68) = 8Square both sides: Square both sides of the equation to eliminate the square root. (sqrt(4x + 68))^2 = 8^2 4x + 68 = 64Subtract 68 to isolate x: Subtract 68 from both sides of the equation to isolate the term with the variable x. 4x + 68 - 68 = 64 - 68 4x = -4Divide by 4 to solve x: Divide both sides of the equation by 4 to solve for x. 4x / 4 = -4 / 4 x = -1

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Solve for $\mathrm{x}$ : $\newline$ $\sqrt{4 x+68}-9=-1$ $\newline$ Answer:

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Q. Solve for

\mathrm{x}

\newline

\sqrt{4 x+68}-9=-1

\newline

Answer:

Add $9$ to isolate square root: Add $9$ to both sides of the equation to isolate the square root on one side. $\newline$ $\sqrt{4x + 68} - 9 + 9 = -1 + 9$ $\newline$ $\sqrt{4x + 68} = 8$
Square both sides: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{4x + 68})^2 = 8^2$ $\newline$ $4x + 68 = 64$
Subtract $68$ to isolate $x$ : Subtract $68$ from both sides of the equation to isolate the term with the variable $x$ . $\newline$ $4x + 68 - 68 = 64 - 68$ $\newline$ $4x = -4$
Divide by $4$ to solve $x$ : Divide both sides of the equation by $4$ to solve for $x$ . $\frac{4x}{4} = \frac{-4}{4}$ $x = -1$