Solve for x. sqrt 3x = sqrt ( –5 + 4x) x = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(3x))^2 = (sqrt(–5 + 4x))^2 3x = –5 + 4xSubtract x terms: Subtract 4x from both sides to get all x terms on one side. 3x - 4x = –5 + 4x - 4x -x = –5Multiply by -1: Multiply both sides by -1 to solve for x. -x * -1 = –5 * -1 x = 5

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Solve for $x$ . $\newline$ $\sqrt{3x} = \sqrt{\left(-5 + 4x\right)}$ $\newline$ $x =$ _____

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Precalculus

Solve radical equations

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Q. Solve for

x

\newline

\sqrt{3x} = \sqrt{\left(-5 + 4x\right)}

\newline

x =

_____

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{3x})^2 = (\sqrt{\text{–}5 + 4x})^2$ $\newline$ $3x = \text{–}5 + 4x$
Subtract $x$ terms: Subtract $4x$ from both sides to get all $x$ terms on one side. $\newline$ $3x - 4x = -5 + 4x - 4x$ $\newline$ $-x = -5$
Multiply by $-1$ : Multiply both sides by $-1$ to solve for x. $\newline$ $-x \times -1 = -5 \times -1$ $\newline$ $x = 5$