Solve for x : sqrt(3x+45)-5=1 Answer:

Add 5 to both sides: Add 5 to both sides of the equation to isolate the square root on one side. sqrt(3x + 45) - 5 + 5 = 1 + 5 sqrt(3x + 45) = 6Square both sides: Square both sides of the equation to eliminate the square root. (sqrt(3x + 45))^2 = 6^2 3x + 45 = 36Subtract 45: Subtract 45 from both sides of the equation to isolate the term with the variable x. 3x + 45 - 45 = 36 - 45 3x = -9Divide by 3: Divide both sides of the equation by 3 to solve for x. 3x / 3 = -9 / 3 x = -3

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Solve for $\mathrm{x}$ : $\newline$ $\sqrt{3 x+45}-5=1$ $\newline$ Answer:

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Q. Solve for

\mathrm{x}

\newline

\sqrt{3 x+45}-5=1

\newline

Answer:

Add $5$ to both sides: Add $5$ to both sides of the equation to isolate the square root on one side. $\newline$ $\sqrt{3x + 45} - 5 + 5 = 1 + 5$ $\newline$ $\sqrt{3x + 45} = 6$
Square both sides: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{3x + 45})^2 = 6^2$ $\newline$ $3x + 45 = 36$
Subtract $45$ : Subtract $45$ from both sides of the equation to isolate the term with the variable $x$ . $\newline$ $3x + 45 - 45 = 36 - 45$ $\newline$ $3x = -9$
Divide by $3$ : Divide both sides of the equation by $3$ to solve for $x$ . $\frac{3x}{3} = \frac{-9}{3}$ $x = -3$