Solve for x : sqrt(3x+19)+16=18 Answer:

Isolate square root: Isolate the square root on one side of the equation by subtracting 16 from both sides. sqrt(3x + 19) + 16 - 16 = 18 - 16 sqrt(3x + 19) = 2Square both sides: Square both sides of the equation to eliminate the square root. (sqrt(3x + 19))^2 = 2^2 3x + 19 = 4Subtract to isolate: Subtract 19 from both sides to isolate the term with the variable x. 3x + 19 - 19 = 4 - 19 3x = -15Divide to solve: Divide both sides by 3 to solve for x. 3x / 3 = -15 / 3 x = -5

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Solve for
x :

sqrt(3x+19)+16=18
Answer:

Solve for $\mathrm{x}$ : $\newline$ $\sqrt{3 x+19}+16=18$ $\newline$ Answer:

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Q. Solve for

\mathrm{x}

\newline

\sqrt{3 x+19}+16=18

\newline

Answer:

Isolate square root: Isolate the square root on one side of the equation by subtracting $16$ from both sides. $\newline$ $\sqrt{3x + 19} + 16 - 16 = 18 - 16$ $\newline$ $\sqrt{3x + 19} = 2$
Square both sides: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{3x + 19})^2 = 2^2$ $\newline$ $3x + 19 = 4$
Subtract to isolate: Subtract $19$ from both sides to isolate the term with the variable $x$ . $\newline$ $3x + 19 - 19 = 4 - 19$ $\newline$ $3x = -15$
Divide to solve: Divide both sides by $3$ to solve for $x$ . $\frac{3x}{3} = \frac{-15}{3}$ $x = -5$