Solve for x : sqrt(2x+41)-17=-12 Answer:

Add 17 to isolate: Add 17 to both sides of the equation to isolate the square root on one side. sqrt(2x + 41) - 17 + 17 = -12 + 17 sqrt(2x + 41) = 5Square to eliminate square root: Square both sides of the equation to eliminate the square root. (sqrt(2x + 41))^2 = 5^2 2x + 41 = 25Subtract 41 to solve: Subtract 41 from both sides of the equation to solve for 2x. 2x + 41 - 41 = 25 - 41 2x = -16Divide to find x: Divide both sides by 2 to solve for x. 2x / 2 = -16 / 2 x = -8

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Solve for
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sqrt(2x+41)-17=-12
Answer:

Solve for $\mathrm{x}$ : $\newline$ $\sqrt{2 x+41}-17=-12$ $\newline$ Answer:

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Q. Solve for

\mathrm{x}

\newline

\sqrt{2 x+41}-17=-12

\newline

Answer:

Add $17$ to isolate: Add $17$ to both sides of the equation to isolate the square root on one side. $\newline$ $\sqrt{2x + 41} - 17 + 17 = -12 + 17$ $\newline$ $\sqrt{2x + 41} = 5$
Square to eliminate square root: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{2x + 41})^2 = 5^2$ $\newline$ $2x + 41 = 25$
Subtract $41$ to solve: Subtract $41$ from both sides of the equation to solve for $2x$ . $\newline$ $2x + 41 - 41 = 25 - 41$ $\newline$ $2x = -16$
Divide to find $x$ : Divide both sides by $2$ to solve for $x$ .
$\frac{2x}{2} = \frac{-16}{2}$
$x = -8$