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Solve for 
x :

sqrt(2x+34)+2=6
Answer:

Solve for x \mathrm{x} :\newline2x+34+2=6 \sqrt{2 x+34}+2=6 \newlineAnswer:

Full solution

Q. Solve for x \mathrm{x} :\newline2x+34+2=6 \sqrt{2 x+34}+2=6 \newlineAnswer:
  1. Isolate square root: Isolate the square root on one side of the equation by subtracting 22 from both sides.\newline2x+34+22=62\sqrt{2x+34} + 2 - 2 = 6 - 2\newline2x+34=4\sqrt{2x+34} = 4
  2. Square both sides: Square both sides of the equation to eliminate the square root.\newline(2x+34)2=42(\sqrt{2x+34})^2 = 4^2\newline2x+34=162x + 34 = 16
  3. Subtract to isolate x: Subtract 3434 from both sides to isolate the term with the variable xx.\newline2x+3434=16342x + 34 - 34 = 16 - 34\newline2x=182x = -18
  4. Divide to solve for x: Divide both sides by 22 to solve for x.\newline2x2=182\frac{2x}{2} = \frac{-18}{2}\newlinex=9x = -9

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