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Solve for 
x, rounding to the nearest hundredth.

4*2^((x)/(5))=1
Answer:

Solve for x x , rounding to the nearest hundredth.\newline42x5=1 4 \cdot 2^{\frac{x}{5}}=1 \newlineAnswer:

Full solution

Q. Solve for x x , rounding to the nearest hundredth.\newline42x5=1 4 \cdot 2^{\frac{x}{5}}=1 \newlineAnswer:
  1. Isolate exponential term: First, we need to isolate the exponential term on one side of the equation. Since we are given 42x/5=14\cdot2^{x/5} = 1, we can divide both sides by 44 to get 2x/5=142^{x/5} = \frac{1}{4}.
  2. Recognize fraction as negative exponent: Next, we recognize that 14\frac{1}{4} is 222^{-2} because 22=122=142^{-2} = \frac{1}{2^2} = \frac{1}{4}. So we can rewrite the equation as 2x5=222^{\frac{x}{5}} = 2^{-2}.
  3. Set exponents equal: Since the bases are the same and the equation is an equality, we can set the exponents equal to each other. This gives us x5=2\frac{x}{5} = -2.
  4. Multiply to isolate xx: To solve for xx, we multiply both sides of the equation by 55 to isolate xx. This gives us x=2×5x = -2 \times 5.
  5. Final solution: Multiplying 2-2 by 55 gives us x=10x = -10.

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