Solve for x and write your answer in simplest form. -4=x-2(-x+(5)/(2))+(6)/(5) Answer: x=

Distribute and Simplify: Distribute the -2 across the parentheses. -4 = x - 2(-x + 5/2) + 6/5 = x - 2(-x) - 2(5/2) + 6/5 = x + 2x - 5 + 6/5Combine Like Terms: Combine like terms. = 3x - 5 + 6/5 To combine the constant terms, convert -5 to a fraction with a denominator of 5. -5 = -5 * (5/5) = -25/5 Now we have: 3x - 25/5 + 6/5Add Fractions: Add the fractions. 3x - 25/5 + 6/5 = 3x - 19/5Isolate Variable Term: Isolate the variable term. To isolate 3x, add 19/5 to both sides of the equation. -4 + 19/5 = 3x To add -4 (which is -20/5) to 19/5, we get: -20/5 + 19/5 = 3x -1/5 = 3xSolve for x: Solve for x by dividing both sides by 3. (-1/5) / 3 = x To divide by 3, multiply by the reciprocal, which is 1/3. (-1/5) * (1/3) = xMultiply Fractions: Multiply the fractions. (-1/5) * (1/3) = -1/15 So, x = -1/15

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Solve for
x and write your answer in simplest form.

-4=x-2(-x+(5)/(2))+(6)/(5)
Answer:
x=

Solve for $x$ and write your answer in simplest form. $\newline$ $-4=x-2\left(-x+\frac{5}{2}\right)+\frac{6}{5}$ $\newline$ Answer: $x=$

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Math Problems

Algebra 1

Multiplication with rational exponents

Full solution

Q. Solve for

x

and write your answer in simplest form.

\newline

-4=x-2\left(-x+\frac{5}{2}\right)+\frac{6}{5}

\newline

Answer:

x=

Distribute and Simplify: Distribute the $-2$ across the parentheses. $\newline$ $-4 = x - 2(-x + \frac{5}{2}) + \frac{6}{5}$ $\newline$ $= x - 2(-x) - 2(\frac{5}{2}) + \frac{6}{5}$ $\newline$ $= x + 2x - 5 + \frac{6}{5}$
Combine Like Terms: Combine like terms. $\newline$ $= 3x - 5 + \frac{6}{5}$ $\newline$ To combine the constant terms, convert $-5$ to a fraction with a denominator of $5$ . $\newline$ $-5 = -5 \times \left(\frac{5}{5}\right) = -\frac{25}{5}$ $\newline$ Now we have: $\newline$ $3x - \frac{25}{5} + \frac{6}{5}$
Add Fractions: Add the fractions. $\newline$ $3x - \frac{25}{5} + \frac{6}{5} = 3x - \frac{19}{5}$
Isolate Variable Term: Isolate the variable term. $\newline$ To isolate $3x$ , add $\frac{19}{5}$ to both sides of the equation. $\newline$ $-4 + \frac{19}{5} = 3x$ $\newline$ To add $-4$ (which is $-\frac{20}{5}$ ) to $\frac{19}{5}$ , we get: $\newline$ $-\frac{20}{5} + \frac{19}{5} = 3x$ $\newline$ $-\frac{1}{5} = 3x$
Solve for x: Solve for x by dividing both sides by $3$ . $\left(-\frac{1}{5}\right) / 3 = x$ To divide by $3$ , multiply by the reciprocal, which is $\frac{1}{3}$ . $\left(-\frac{1}{5}\right) \cdot \left(\frac{1}{3}\right) = x$
Multiply Fractions: Multiply the fractions. $\newline$ $(-\frac{1}{5}) \times (\frac{1}{3}) = -\frac{1}{15}$ $\newline$ So, $x = -\frac{1}{15}$