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Solve for x: $(3x+9) \div 2 = (1x+4) \div 8$

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Add, subtract, multiply, or divide two fractions

Full solution

Q. Solve for x:

(3x+9) \div 2 = (1x+4) \div 8

Eliminate denominators: Simplify both sides of the equation by eliminating the denominators. $\newline$ To do this, we can find a common denominator for $2$ and $8$ , which is $8$ . We will multiply both sides of the equation by $8$ to get rid of the fractions. $\newline$ $(3x+9)\div 2 \times 8 = (1x+4)\div 8 \times 8$
Perform multiplication: Perform the multiplication on both sides. $\newline$ $(3x+9) \times 4 = (1x+4) \times 1$ $\newline$ $12x + 36 = 1x + 4$
Isolate variable x: Isolate the variable x on one side of the equation. $\newline$ To do this, we will subtract $1x$ from both sides of the equation. $\newline$ $12x + 36 - 1x = 1x + 4 - 1x$ $\newline$ $11x + 36 = 4$
Subtract $36$ : Subtract $36$ from both sides to solve for $x$ . $\newline$ $11x + 36 - 36 = 4 - 36$ $\newline$ $11x = -32$
Divide by $11$ : Divide both sides by $11$ to find the value of x. $\newline$ $11x \div 11 = -32 \div 11$ $\newline$ $x = -\frac{32}{11}$

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