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{:[(3x-2)/(3x+1)=3],[x=]:}

Solve for x x .\newline3x23x+1=3x= \begin{array}{l} \frac{3 x-2}{3 x+1}=3 \\ x= \end{array}

Full solution

Q. Solve for x x .\newline3x23x+1=3x= \begin{array}{l} \frac{3 x-2}{3 x+1}=3 \\ x= \end{array}
  1. Cross-multiplying to eliminate the fraction: Solve the equation (3x2)/(3x+1)=3(3x-2)/(3x+1) = 3. To do this, we can start by cross-multiplying to eliminate the fraction. (3x2)=3×(3x+1)(3x - 2) = 3 \times (3x + 1)
  2. Distributing the 33 on the right side: Distribute the 33 on the right side of the equation.(3x2)=9x+3(3x - 2) = 9x + 3
  3. Moving terms involving xx to one side: Move all terms involving xx to one side of the equation.3x9x=3+23x - 9x = 3 + 2
  4. Combining like terms: Combine like terms.\newline6x=5-6x = 5
  5. Solving for x by dividing both sides: Solve for x by dividing both sides by 6-6.\newlinex=56x = \frac{5}{-6}

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