Solve for v : {:[-(9)/(8)=v-(1)/(2)],[v=◻]:}

Given Equation: We are given the equation: -(9/8) = v - (1/2) We need to solve for v.Isolate v: To isolate v, we will add (1/2) to both sides of the equation to move the term involving v to one side and the constants to the other side. -(9/8) + (1/2) = v - (1/2) + (1/2)Add Fractions: Before we can add the fractions, we need a common denominator. The least common denominator for 8 and 2 is 8. So we convert (1/2) to (4/8) to have the same denominator. -(9/8) + (4/8) = vCombine Fractions: Now we add the fractions on the left side: -(9/8) + (4/8) = -(5/8) So, -(5/8) = vFinal Value of v: We have isolated v and found its value: v = -(5/8)

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Solve for
v :

{:[-(9)/(8)=v-(1)/(2)],[v=◻]:}

Solve for $v$ : $\begin{align} -\frac{9}{8} &= v - \frac{1}{2}, \ v &= \Box \end{align}$

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Algebra 2

Domain and range of absolute value functions: equations

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Q. Solve for

v

\begin{align*} -\frac{9}{8} &= v - \frac{1}{2}, \ v &= \Box \end{align*}

Given Equation: We are given the equation: $\newline$ $-\frac{9}{8} = v - \frac{1}{2}$ $\newline$ We need to solve for $v$ .
Isolate v: To isolate v, we will add $(1/2)$ to both sides of the equation to move the term involving v to one side and the constants to the other side. $-\left(\frac{9}{8}\right) + \left(\frac{1}{2}\right) = v - \left(\frac{1}{2}\right) + \left(\frac{1}{2}\right)$
Add Fractions: Before we can add the fractions, we need a common denominator. The least common denominator for $8$ and $2$ is $8$ . So we convert $(1/2)$ to $(4/8)$ to have the same denominator. $-(9/8) + (4/8) = v$
Combine Fractions: Now we add the fractions on the left side: $\newline$ $-\frac{9}{8} + \frac{4}{8} = -\frac{5}{8}$ $\newline$ So, $-\frac{5}{8} = v$
Final Value of v: We have isolated v and found its value: $\newline$ v = $-\frac{5}{8}$