Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for tt.\newline(t−1)(t−7)=0(t - 1)(t - 7) = 0\newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlinet=t = _____ or t=t = _____

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Solve a quadratic equation using the zero product propertyright chevron icon

Full solution

Q. Solve for tt.\newline(t−1)(t−7)=0(t - 1)(t - 7) = 0\newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlinet=t = _____ or t=t = _____
  1. Identify Property: Identify the property to use in solving the given equation.\newlineProperty: Zero product property
  2. Solve for tt (t−1t-1): Solve for tt when (t−1)=0(t − 1) = 0.\newlineAdd 11 to both sides of the equation.\newlinet−1+1=0+1t − 1 + 1 = 0 + 1\newlinet=1t = 1
  3. Solve for tt (t−7t-7): Solve for tt when (t−7)=0(t − 7) = 0.\newlineAdd 77 to both sides of the equation.\newlinet−7+7=0+7t − 7 + 7 = 0 + 7\newlinet=7t = 7
  4. Two Solutions for (t−1)(t−7)(t-1)(t-7): The equation (t−1)(t−7)=0(t − 1)(t − 7) = 0 has two solutions.t−1=0t − 1 = 0 implies t=1t = 1.t−7=0t − 7 = 0 implies t=7t = 7.Values of tt: 1,71, 7

More problems from Solve a quadratic equation using the zero product property

Question
The function h(t)=−16t2+144h(t) = -16t^{2} + 144 represents the height, h(t)h(t), in feet, of an object from the ground at tt seconds after it is dropped. A realistic domain (for time) for this function is:\newline(A)(A) −3≤t≤3-3 \leq t \leq 3\newline(B)(B) 0≤t≤30 \leq t \leq 3\newline(C)(C) 0≤h≤1440 \leq h \leq 144\newline(D)(D) all real numbers
Get tutor helpright-arrow

Posted 8 months ago

Question
Деление с остатком
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=x2+40x−20y = x^2 + 40x - 20\newliney=40x−4y = 40x - 4\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=−36x+26y = -36x + 26\newliney=x2−46x−13y = x^2 - 46x - 13\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=32x2+32x−23y = 32x^2 + 32x - 23\newliney=32x+9y = 32x + 9\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=x2+12x−41y = x^2 + 12x - 41\newliney=17x+9y = 17x + 9\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=x2−43x−14y = x^2 - 43x - 14\newliney=−45x+34y = -45x + 34\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve the system of equations.\newliney=14x−26y = 14x - 26\newliney=2x2+14x−34y = 2x^2 + 14x - 34\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
Get tutor helpright-arrow

Posted 8 months ago

Question
Find the discriminant.\newline3u2−8u+4=03u^2 - 8u + 4 = 0
Get tutor helpright-arrow

Posted 8 months ago

Question
Find the discriminant.\newline7w2+5w+8=07w^2 + 5w + 8 = 0
Get tutor helpright-arrow

Posted 8 months ago

View all (2)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant