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Let’s check out your problem:
Solve for
s
s
s
.
\newline
5
s
=
6
s
−
7
\sqrt{5s} = \sqrt{6s - 7}
5
s
=
6
s
−
7
\newline
s
=
s =
s
=
_____
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Math Problems
Precalculus
Solve radical equations
Full solution
Q.
Solve for
s
s
s
.
\newline
5
s
=
6
s
−
7
\sqrt{5s} = \sqrt{6s - 7}
5
s
=
6
s
−
7
\newline
s
=
s =
s
=
_____
Square both sides:
Square both sides of the equation to eliminate the square roots.
\newline
(
5
s
)
2
=
(
6
s
−
7
)
2
(\sqrt{5s})^2 = (\sqrt{6s - 7})^2
(
5
s
)
2
=
(
6
s
−
7
)
2
\newline
5
s
=
6
s
−
7
5s = 6s - 7
5
s
=
6
s
−
7
Subtract
6
6
6
s:
Subtract
6
s
6s
6
s
from both sides to get all terms with
s
s
s
on one side.
\newline
5
s
−
6
s
=
6
s
−
6
s
−
7
5s - 6s = 6s - 6s - 7
5
s
−
6
s
=
6
s
−
6
s
−
7
\newline
−
1
s
=
−
7
-1s = -7
−
1
s
=
−
7
Divide by
−
1
-1
−
1
:
Divide both sides by
−
1
-1
−
1
to solve for
s
s
s
.
\newline
−
1
s
/
−
1
=
−
7
/
−
1
-1s / -1 = -7 / -1
−
1
s
/
−
1
=
−
7/
−
1
\newline
s
=
7
s = 7
s
=
7
More problems from Solve radical equations
Question
What is the domain of this function?
\newline
y
=
x
y = \sqrt{x}
y
=
x
\newline
Choices:
\newline
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x
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{
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x
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\newline
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Question
Find the real-number root.
\newline
16
\sqrt{16}
16
\newline
\newline
Write your answer in simplified form.
\newline
_
_
_
_
\_\_\_\_
____
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Posted 1 year ago
Question
Find the real-number root.
\newline
9
16
\sqrt{\frac{9}{16}}
16
9
\newline
Simplify your answer and write it as a decimal or as a proper or improper fraction.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
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Posted 1 year ago
Question
Find the real-number root using a calculator. Round your answer to the nearest thousandth.
\newline
`\sqrt{957} `
\newline
_______
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Posted 1 year ago
Question
Multiply. Write your answer in simplest form.
\newline
273
×
42
\sqrt{273} \times \sqrt{42}
273
×
42
\newline
______
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Posted 1 year ago
Question
Simplify.
\newline
63
4
\sqrt{\frac{63}{4}}
4
63
\newline
______
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Posted 1 year ago
Question
Simplify. Rationalize the denominator.
\newline
−
4
9
−
2
\frac{-4}{9 - \sqrt{2}}
9
−
2
−
4
\newline
______
Get tutor help
Posted 1 year ago
Question
Solve for
z
z
z
.
\newline
16
=
z
16 = \sqrt{z}
16
=
z
\newline
z
=
z =
z
=
_____
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Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
8
=
p
8 = \sqrt{p}
8
=
p
\newline
p
=
p =
p
=
_____
Get tutor help
Posted 1 year ago
Question
Solve for
p
p
p
.
\newline
4
p
=
10
+
3
p
\sqrt{4p} = \sqrt{10 + 3p}
4
p
=
10
+
3
p
\newline
p
=
p =
p
=
_____
Get tutor help
Posted 9 months ago
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