Solve for r. sqrt ( r + 6) = sqrt –2r r = _____

Square Both Sides: Square both sides of the equation to eliminate the square roots. (sqrt(r + 6))^2 = (sqrt(-2r))^2 r + 6 = -2rIsolate Variable r: Isolate the variable r on one side of the equation. Add 2r to both sides of the equation. r + 2r + 6 = -2r + 2r 3r + 6 = 0Subtract to Solve: Subtract 6 from both sides of the equation to solve for r. 3r + 6 - 6 = 0 - 6 3r = -6Divide to Find Value: Divide both sides of the equation by 3 to find the value of r. 3r / 3 = -6 / 3 r = -2

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Solve for $r$ . $\newline$ $\sqrt{r + 6} = \sqrt{-2r}$ $\newline$ $r =$ _____

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Q. Solve for

r

\newline

\sqrt{r + 6} = \sqrt{-2r}

\newline

r =

_____

Square Both Sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{r + 6})^2 = (\sqrt{-2r})^2$ $\newline$ $r + 6 = -2r$
Isolate Variable $r$ : Isolate the variable $r$ on one side of the equation. $\newline$ Add $2r$ to both sides of the equation. $\newline$ $r + 2r + 6 = -2r + 2r$ $\newline$ $3r + 6 = 0$
Subtract to Solve: Subtract $6$ from both sides of the equation to solve for $r$ . $\newline$ $3r + 6 - 6 = 0 - 6$ $\newline$ $3r = -6$
Divide to Find Value: Divide both sides of the equation by $3$ to find the value of $r$ . $\newline$ $\frac{3r}{3} = \frac{-6}{3}$ $\newline$ $r = -2$