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Let’s check out your problem:
Solve for
r
r
r
.
\newline
8
r
=
6
r
+
2
\sqrt{8r} = \sqrt{6r + 2}
8
r
=
6
r
+
2
\newline
r
=
r =
r
=
_____
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Math Problems
Precalculus
Solve radical equations
Full solution
Q.
Solve for
r
r
r
.
\newline
8
r
=
6
r
+
2
\sqrt{8r} = \sqrt{6r + 2}
8
r
=
6
r
+
2
\newline
r
=
r =
r
=
_____
Square both sides:
Square both sides of the equation to eliminate the square roots.
\newline
(
8
r
)
2
=
(
6
r
+
2
)
2
(\sqrt{8r})^2 = (\sqrt{6r + 2})^2
(
8
r
)
2
=
(
6
r
+
2
)
2
\newline
8
r
=
6
r
+
2
8r = 6r + 2
8
r
=
6
r
+
2
Subtract to isolate:
Subtract
6
r
6r
6
r
from both sides to isolate the variable term on one side.
\newline
8
r
−
6
r
=
6
r
+
2
−
6
r
8r - 6r = 6r + 2 - 6r
8
r
−
6
r
=
6
r
+
2
−
6
r
\newline
2
r
=
2
2r = 2
2
r
=
2
Divide to solve:
Divide both sides by
2
2
2
to solve for
r
r
r
.
2
r
2
=
2
2
\frac{2r}{2} = \frac{2}{2}
2
2
r
=
2
2
r
=
1
r = 1
r
=
1
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\newline
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\newline
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\newline
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\newline
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\newline
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\newline
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Question
Solve for
z
z
z
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\newline
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Solve for
p
p
p
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\newline
8
=
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\newline
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Solve for
p
p
p
.
\newline
4
p
=
10
+
3
p
\sqrt{4p} = \sqrt{10 + 3p}
4
p
=
10
+
3
p
\newline
p
=
p =
p
=
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