Solve for r. sqrt –4r = sqrt ( –5r − 1) r = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–4r))^2 = (sqrt(–5r − 1))^2 –4r = –5r − 1Add 5r: Add 5r to both sides of the equation to get all the r terms on one side. –4r + 5r = –5r + 5r − 1 r = −1

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Solve for $r$ . $\newline$ $\sqrt{\,-4r} = \sqrt{\,-5r -1}$ $\newline$ $r = \,\_\_\_\_$

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Q. Solve for

r

\newline

\sqrt{\,-4r} = \sqrt{\,-5r -1}

\newline

r = \,\_\_\_\_

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-4r})^2 = (\sqrt{-5r - 1})^2$ $\newline$ $-4r = -5r - 1$
Add $5r$ : Add $5r$ to both sides of the equation to get all the $r$ terms on one side. $\newline$ $-4r + 5r = -5r + 5r - 1$ $\newline$ $r = -1$