Solve for r. sqrt –2r = sqrt ( –2 − 4r) r = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–2r))^2 = (sqrt(–2 − 4r))^2 –2r = –2 − 4rAdd r terms: Add 4r to both sides of the equation to get all the r terms on one side. –2r + 4r = –2 − 4r + 4r 2r = –2Divide to solve: Divide both sides by 2 to solve for r. 2r / 2 = –2 / 2 r = –1

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Solve for $r$ . $\newline$ $\sqrt{\,-2r} = \sqrt{(\,-2 - 4r)}$ $\newline$ $r =$ $\_\_\_\_$

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Q. Solve for

r

\newline

\sqrt{\,-2r} = \sqrt{(\,-2 - 4r)}

\newline

r =

\_\_\_\_

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ (\sqrt{-2r})^2 = (\sqrt{-2 - 4r})^2$\newline$ $\newline$ $-2r = -2 - 4r$
Add $r$ terms: Add $4r$ to both sides of the equation to get all the $r$ terms on one side. $\newline$ $-2r + 4r = -2 - 4r + 4r$ $\newline$ $2r = -2$
Divide to solve: Divide both sides by $2$ to solve for $r$ . $\frac{2r}{2} = \frac{-2}{2}$ $r = -1$