Solve for r. {:[(4)/(r)=(5)/(7)],[r=◻]:}

Set up equation: Set up the equation from the given problem. We have the equation (4/r) = (5/7). To solve for r, we need to find a value for r that makes this equation true.Cross-multiply: Cross-multiply to solve for r. Cross-multiplying gives us 4 * 7 = 5 * r.Perform multiplication: Perform the multiplication on both sides of the equation. 4 * 7 = 28 and 5 * r = 5r. So, we have 28 = 5r.Divide for r: Divide both sides of the equation by 5 to solve for r. 28 / 5 = 5r / 5.Calculate r: Calculate the value of r. 28 / 5 = 5.6, so r = 5.6.

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Solve for
r.

{:[(4)/(r)=(5)/(7)],[r=◻]:}

Solve for $r$ .\begin{align} \left(\frac{4}{r}\right)&=\left(\frac{5}{7}\right),\ r&= \end{align}

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Grade 8

Write variable expressions for arithmetic sequences

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Q. Solve for

r

.\begin{align*} \left(\frac{4}{r}\right)&=\left(\frac{5}{7}\right),\ r&= \end{align*}

Set up equation: Set up the equation from the given problem. $\newline$ We have the equation $(\frac{4}{r}) = (\frac{5}{7})$ . To solve for $r$ , we need to find a value for $r$ that makes this equation true.
Cross-multiply: Cross-multiply to solve for $r$ . Cross-multiplying gives us $4 \times 7 = 5 \times r$ .
Perform multiplication: Perform the multiplication on both sides of the equation. $\newline$ $4 \times 7 = 28$ and $5 \times r = 5r$ . $\newline$ So, we have $28 = 5r$ .
Divide for $r$ : Divide both sides of the equation by $5$ to solve for $r$ . $\frac{28}{5} = \frac{5r}{5}$ .
Calculate $r$ : Calculate the value of $r$ . $\frac{28}{5} = 5.6$ , so $r = 5.6$ .