Solve for q. sqrt –7q = sqrt ( 10 − 2q) q = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–7q))^2 = (sqrt(10 − 2q))^2 –7q = 10 − 2qAdd q terms: Add 2q to both sides to get all the q terms on one side. –7q + 2q = 10 − 2q + 2q –5q = 10Divide by -5: Divide both sides by -5 to solve for q. –5q / -5 = 10 / -5 q = -2

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Solve for $q$ . $\newline$ $\sqrt{\,-7q} = \sqrt{(\,10 - 2q)}$ $\newline$ $q = \,\_\_\_\_$

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Q. Solve for

q

\newline

\sqrt{\,-7q} = \sqrt{(\,10 - 2q)}

\newline

q = \,\_\_\_\_

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-7q})^2 = (\sqrt{10 - 2q})^2$ $\newline$ $-7q = 10 - 2q$
Add $q$ terms: Add $2q$ to both sides to get all the $q$ terms on one side. $\newline$ $–7q + 2q = 10 − 2q + 2q$ $\newline$ $–5q = 10$
Divide by $-5$ : Divide both sides by $-5$ to solve for q. $\newline$ $-5q / -5 = 10 / -5$ $\newline$ $q = -2$