Solve for q. {:[(2)/(2q+3)=(1)/(8)],[q=]:}

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Solve for  q.  {:[(2)/(2q+3)=(1)/(8)],[q=]:}

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Isolate variable term: Isolate the variable term in the first equation. To isolate the variable term, we need to get rid of the fraction by multiplying both sides of the equation by the denominator of the left side, which is (2q + 3). (2)/(2q+3) * (2q + 3) = (1)/(8) * (2q + 3)Perform multiplication: Perform the multiplication on both sides. On the left side, the (2q + 3) cancels out, leaving us with 2. On the right side, we distribute (1)/(8) to both terms in the parentheses. 2 = (1)/(8) * 2q + (1)/(8) * 3Simplify right side: Simplify the right side of the equation. 2 = (2q)/(8) + (3)/(8) 2 = (1)/(4)q + (3)/(8)Get terms on one side: Get all terms containing q on one side and constant terms on the other side. To do this, we subtract (3)/(8) from both sides of the equation. 2 - (3)/(8) = (1)/(4)qConvert to common denominator: Convert the left side to a common denominator to subtract the fractions. The common denominator for 2 and (3)/(8) is 8, so we convert 2 to (16)/(8). (16)/(8) - (3)/(8) = (1)/(4)qPerform subtraction: Perform the subtraction on the left side. (16)/(8) - (3)/(8) = (13)/(8) (13)/(8) = (1)/(4)qSolve for q: Solve for q by multiplying both sides by the reciprocal of (1)/(4). The reciprocal of (1)/(4) is 4, so we multiply both sides by 4 to isolate q. 4 * (13)/(8) = qSimplify multiplication: Simplify the multiplication to find the value of q. 4 * (13)/(8) = (52)/(8) q = (52)/(8) q = 6.5

Solve for $q$ . $\newline$ $\begin{array}{l} \frac{2}{2 q+3}=\frac{1}{8} \\ q=\square \end{array}$

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Solve for $q$ . $\newline$ $\begin{array}{l} \frac{2}{2 q+3}=\frac{1}{8} \\ q=\square \end{array}$