Solve for q. {:[(10)/(9)=(3)/(q)],[q=]:}

Set up proportion equation: Set up the proportion as an equation. (10/9) = (3/q) We need to find the value of q that makes this equation true.Cross-multiply to solve: Cross-multiply to solve for q. 10 * q = 9 * 3 This step involves multiplying both sides of the equation by 9q to eliminate the fractions.Perform the multiplication: Perform the multiplication. 10q = 27 Now we have a simple equation to solve for q.Divide to isolate q: Divide both sides by 10 to isolate q. q = 27 / 10 This step involves dividing both sides of the equation by 10 to solve for q.Simplify the fraction: Simplify the fraction. q = 2.7 We have found the value of q.

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Solve for
q.

{:[(10)/(9)=(3)/(q)],[q=]:}

Solve for $q$ . $\newline$ $\begin{array}{l} \frac{10}{9}=\frac{3}{q} \\ q=\square \end{array}$

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Math Problems

Grade 6

Multiply using the distributive property

Full solution

Q. Solve for

q

\newline

\begin{array}{l} \frac{10}{9}=\frac{3}{q} \\ q=\square \end{array}

Set up proportion equation: Set up the proportion as an equation. $\newline$ $(\frac{10}{9}) = (\frac{3}{q})$ $\newline$ We need to find the value of $q$ that makes this equation true.
Cross-multiply to solve: Cross-multiply to solve for $q$ . $\newline$ $10 \times q = 9 \times 3$ $\newline$ This step involves multiplying both sides of the equation by $9q$ to eliminate the fractions.
Perform the multiplication: Perform the multiplication. $10q = 27$ Now we have a simple equation to solve for $q$ .
Divide to isolate q: Divide both sides by $10$ to isolate $q$ . $\newline$ $q = \frac{27}{10}$ $\newline$ This step involves dividing both sides of the equation by $10$ to solve for $q$ .
Simplify the fraction: Simplify the fraction. $q = 2.7$ We have found the value of $q$ .