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Solve for pp.\newline(8p3)=5p\sqrt{(-8p - 3)} = \sqrt{-5p}\newlinep=p = _____

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Q. Solve for pp.\newline(8p3)=5p\sqrt{(-8p - 3)} = \sqrt{-5p}\newlinep=p = _____
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(8p3)2=(5p)2(\sqrt{-8p - 3})^2 = (\sqrt{-5p})^2\newline8p3=5p-8p - 3 = -5p
  2. Add pp terms: Add 8p8p to both sides to get all the pp terms on one side.\newline8p+8p3=5p+8p−8p + 8p − 3 = −5p + 8p\newline3=3p−3 = 3p
  3. Divide by 33: Divide both sides by 33 to solve for pp.33=3p3\frac{-3}{3} = \frac{3p}{3}p=1p = -1

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