Solve for k. {:[(10)/(3)=(k)/(9)],[k=]:}

Identify Method: Identify the cross-multiplication method to solve the proportion. To solve for k in the equation (10/3) = (k/9), we can cross-multiply to find the value of k.Cross-Multiply Terms: Cross-multiply the terms in the equation. (10/3) = (k/9) implies that 10 * 9 = 3 * k.Perform Multiplication: Perform the multiplication on both sides. 10 * 9 = 90 and 3 * k = 3k. So, 90 = 3k.Divide Equation: Divide both sides of the equation by 3 to solve for k. 90 = 3k implies that k = 90 / 3.Calculate Value: Calculate the value of k. k = 90 / 3 = 30.

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Solve for
k.

{:[(10)/(3)=(k)/(9)],[k=]:}

Solve for $k$ . $\newline$ $\begin{array}{l} \frac{10}{3}=\frac{k}{9} \\ k= \end{array}$

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Math Problems

Grade 6

Multiply using the distributive property

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Q. Solve for

k

\newline

\begin{array}{l} \frac{10}{3}=\frac{k}{9} \\ k= \end{array}

Identify Method: Identify the cross-multiplication method to solve the proportion. $\newline$ To solve for $k$ in the equation $(\frac{10}{3}) = (\frac{k}{9})$ , we can cross-multiply to find the value of $k$ .
Cross-Multiply Terms: Cross-multiply the terms in the equation. $\newline$ $(\frac{10}{3}) = (\frac{k}{9})$ implies that $10 \times 9 = 3 \times k$ .
Perform Multiplication: Perform the multiplication on both sides. $\newline$ $10 \times 9 = 90$ and $3 \times k = 3k$ . $\newline$ So, $90 = 3k$ .
Divide Equation: Divide both sides of the equation by $3$ to solve for $k$ . $\newline$ $90 = 3k$ implies that $k = \frac{90}{3}$ .
Calculate Value: Calculate the value of $k$ . $k = \frac{90}{3} = 30$ .