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Solve for jj.\newline8+3j=j\sqrt{\,-8 + 3j} = \sqrt{j}\newlinej=____j = \,\_\_\_\_

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Q. Solve for jj.\newline8+3j=j\sqrt{\,-8 + 3j} = \sqrt{j}\newlinej=____j = \,\_\_\_\_
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(8+3j)2=(j)2(\sqrt{-8 + 3j})^2 = (\sqrt{j})^2\newline8+3j=j-8 + 3j = j
  2. Combine jj terms: Since we have jj on both sides of the equation, we need to get all the jj terms on one side to solve for jj.3jj=83j - j = 82j=82j = 8
  3. Isolate jj: Divide both sides by 22 to isolate jj.2j2=82\frac{2j}{2} = \frac{8}{2}j=4j = 4

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