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Solve for jj.\newline7j=2j+10\sqrt{7j} = \sqrt{2j + 10}\newlinej=j = _____

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Q. Solve for jj.\newline7j=2j+10\sqrt{7j} = \sqrt{2j + 10}\newlinej=j = _____
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(7j)2=(2j+10)2(\sqrt{7j})^2 = (\sqrt{2j + 10})^2\newline7j=2j+107j = 2j + 10
  2. Subtract jj terms: Subtract 2j2j from both sides to get all the jj terms on one side.\newline7j2j=2j+102j7j - 2j = 2j + 10 - 2j\newline5j=105j = 10
  3. Divide by 55: Divide both sides by 55 to solve for jj.5j5=105\frac{5j}{5} = \frac{10}{5}j=2j = 2

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