Solve for j. sqrt –2j = sqrt ( –6 − 4j) j = _____

Square both sides: Square both sides of the equation to eliminate the square roots. (sqrt(–2j))^2 = (sqrt(–6 – 4j))^2 –2j = –6 – 4jAdd j terms: Add 4j to both sides of the equation to get all the j terms on one side. –2j + 4j = –6 – 4j + 4j 2j = –6Divide by 2: Divide both sides by 2 to solve for j. 2j / 2 = –6 / 2 j = –3

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Solve for $j$ . $\newline$ $\sqrt{\,-2j} = \sqrt{\,-6 - 4j}$ $\newline$ $j = \,\_\_\_\_$

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Q. Solve for

j

\newline

\sqrt{\,-2j} = \sqrt{\,-6 - 4j}

\newline

j = \,\_\_\_\_

Square both sides: Square both sides of the equation to eliminate the square roots. $\newline$ $(\sqrt{-2j})^2 = (\sqrt{-6 - 4j})^2$ $\newline$ $-2j = -6 - 4j$
Add $j$ terms: Add $4j$ to both sides of the equation to get all the $j$ terms on one side. $\newline$ $-2j + 4j = -6 - 4j + 4j$ $\newline$ $2j = -6$
Divide by $2$ : Divide both sides by $2$ to solve for $j$ . $\frac{2j}{2} = \frac{-6}{2}$ $j = -3$